# Probability Of Error Of Qpsk Fading

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can you **help me to solve this** problem? The system returned: (22) Invalid argument The remote host or network may be down. The system returned: (22) Invalid argument The remote host or network may be down. I already did the scaling for the symbols. check my blog

The system returned: (22) Invalid argument The remote host or network may be down. and by using OPTIMUM COMBINIG which incerease the SINR, if you have code of it than plz send me, i will be very thank ful to u for this.. At the receiver, based on the decoded constellation point, convert that to bits. DSP log Google Home About Blog Analog Channel Coding DSP GATE MIMO Modulation OFDM Subscribe (6 votes, average: 5.00 out of 5) Loading ... http://www.dsplog.com/2007/11/06/symbol-error-rate-for-4-qam/

## Bit Error Probability For Qpsk

Reply Rabbi June 26, 2009 at 8:00 am Hi, thanx for prompt reply. I find **problem of** simulation Asymmetric QPSK. However I am getting nice MSE curve after interpolation. Quick example : clear all; close all; snr_in_dB = [-10:10]; snr1 = exp(snr_in_dB*log(10)/10); snr2 = 10.^(snr_in_dB/10); err = (snr1-snr2)*(snr1-snr2)'/length(snr1-snr2) err_db = 10*log10((snr1-snr2)*(snr1-snr2)'/length(snr1-snr2)) = -304.56!!!

The data-point **could stay where** it is. Am directly generating the random constellation points. For QPSK we need to send fc-1/2T Hz to fc+1/2T Hz. Oqpsk Vs Qpsk The decision boundary can be the line drawn at an angle of 45degree from the origin (passing through the quadrant occupied by s2).

To debug the probable phase issue: you may find ‘ideal' channel frequency response and obtain BER with ideal channel then compute MSE as the difference between ideal channel and interpolated channel. Error Probability In Flat Fading Channels If we need to do non-coherent demodulation, we need to do some tweakings to the transmit signal to enable the receiver to be non-coherent. Your cache administrator is webmaster. The results of your first report show a marginal link for the wireless LAN and a strong link for the satellite connection.

Well, regarding the noise removal with halfband width, may I try to argue as follows: even if we pass the full bandwidth, we will be ignoring the imaginary part of the Bpsk Probability Of Error Derivation I am not doing any phase error correction. area outside the blue region). . Reply nano686 October 10, 2008 at 7:59 am Thanks Krishma and Richard alot!

- Also, as of now, you are defining dsource and decis in decimal values - {00, 01, 10, 11} -> {zero, one, ten, eleven}.
- Your cache administrator is webmaster.
- Reply Krishna Sankar June 30, 2008 at 5:16 am @Richard Mayo: Thanks.
- Reply Krishna Sankar October 18, 2012 at 5:37 am @Gurimandeep: Assuming a gray coded modulation, i.e each symbol error causes only one bit error, conversion of symbol error rate to ber
- Tks in advance.
- Reply thanesh November 25, 2009 at 7:55 am Hi Krishna i was trying to simulate qpsk in ofdm like the one you did for bpsk in ofdm.
- or the value of Eb should change for each of the modulation schemes such as 2 for QPSK (2 bits) 4 for 16QAM? (4-bits) ??
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- What I mean is, the symbol error rate that you obtained versus Es/No would it be the same as saying Symbol error rate vs SNR?

## Error Probability In Flat Fading Channels

My perspective was on the way we assign bit pattern to constellation points. Did you mention that in the context of digital communication system? Bit Error Probability For Qpsk Does the same analysis hold if the noise is only phase noise, or would the effect be reduced by 1/(sqrt(2)) ? Ber For Qpsk Matlab Code Google+ Facebook DSP ANALOG & DSP Complex to Real DSP DesignLine DSP Guide DSPRelated Octave Octave-Forge Online Scientific Calculator (from EEWeb.com) AboutArticlesAdvertiseBlogHomeSearch Performance Optimization WordPress Plugins by W3 EDGE Skip to

At least, that's what I was taught in school… So, if the bandwidth is halved, the noise in the passband is also reduced by 3dB (assuming AWGN). click site Generated Mon, 24 Oct 2016 14:19:57 GMT by s_wx1126 (squid/3.5.20) ERROR The requested URL could not be retrieved The following error was encountered while trying to retrieve the URL: http://0.0.0.6/ Connection For finding Packet Error Rate probability, we will group N bits to form a packet, and flag that packet as error if anyone of the bit in that packet is in Although the Es/No for QPSK is 3dB worse than BPSK. Oqpsk Modulation

They also want to improve the wireless LAN connection to support a probability of error equal to 10-5. Commun., 1976.[3] Cho, K., and Yoon, D., "On the general BER expression of one- and two-dimensional amplitude modulations", IEEE Trans. Reply Hassan November 16, 2010 at 10:09 pm Hi, I need the Matlab code example for simulation of BER vs SNR for M-ary 64QAM. http://spamdestructor.com/probability-of/probability-of-bit-error-for-qpsk.php Therefore the noise in QPSK receiver would also be half of BPSK.

The probability of symbol error is, . Oqpsk Modulation And Demodulation But the following posts on diversity might be of help http://www.dsplog.com/tag/diversity/ Reply siva January 22, 2013 at 9:57 pm Hello Krishna sir, I want to do SPECTRUM SENSNG USING ENERGY DETECTION Please help me.

## How the deceision region will look like and how to calculate BER for this so called 3QAM.

John Reply Krishna Sankar March 25, 2009 at 5:53 am @John: For the simulations in this article, Es/No is same as SNR. Anyhow just to add that : most of the articles in this blog refers to symbol error probability or bit error probability. Since each constellation has two bits, the probability of bit error is approximately probability of symbol error by 2. Probability Of Error In Bpsk IT-10, pp. 339-350, 1964.[6] Simon, M.

Once the SER results are obtained, getting the BER results should be straightforward. Please try the request again. Click here to download: Matlab/Octave script for computing the symbol error rate for QPSK modulation Figure: Symbol Error Rate for QPSK (4QAM) modulation Observations 1. More about the author All the best.

Since a symbol can carry more than one bit, each symbol error might result in a more than one bits to be in error. How can i calculate the bit error for qpsk (4qam) ? K , Hinedi, S. I will be grateful to you if you give me that process.

When Gray coding is used for mapping the bits to the constellation points, there is only one bit in error when noise causes constellation to be shifted to the adjacent quadrant. However, from a quick browsing, I found the article: Specifying Local Oscillator Phase Noise Performance: How Good is Good Enough? They want to increase their data rate to 20 Mbps. Vary the diversity order from 1 to 20.for L = 1:20 ber(:,L) = berfading(EbNo,'qam',16,L); end Plot the results.semilogy(EbNo,ber,'b') text(18.5, 0.02, sprintf('L=%d',1)) text(18.5, 1e-11, sprintf('L=%d',20)) title('QAM over fading channel with diversity order

Please try the request again. With thanks. On that binary sequence you can group them to two bits, and based on the two bits convert them to constellation points. Sorry, I have not studied the BER vs phase noise.

Good luck. Notice that adjacent constellation symbols differ by only one bit. bref how to create an programm principal with other sous program Reply Krishna Sankar April 14, 2010 at 4:40 am @david: To modularize the code, You can use functions in Matlab if it is possible the one used by IEEE 802.15.4?

Commun., Vol. 50, Number 7, pp. 1074-1080, 2002.[4] Lee, P. The probability of being decoded correctly is, . The system returned: (22) Invalid argument The remote host or network may be down. Reply M_abs September 1, 2009 at 11:54 pm Thanks Krishna for ur decorated resource .

However, since BPSK is a real signal, the spectrum is symmetric around fc. Reply Krishna Sankar June 12, 2008 at 5:36 am @ansar: Let me try to answer" If s2 is not present, the area occupied by s2 can be used by both s3 Y=XH'+N;-> X=Y/H' ; H' is the estimated channel and all parameters r in time domain. The sensitivity of the receiver is also reduced by 3dB.